Label a 1.5 eppendorf tube for each sample so you can generate a stock PCR solution of 13.33 ng/ul the final volume being 20uL.
Each tube must be labelled as stock 13.33 ng/ul, sample name, and RG name.
The important formula here is:
n = c*V with n being the amount in ng, c the concentration in ng/ul, and V the volume.
You want V = 20ul and c =13.33 ng/ul. This means you will have 267ng in 20 ul.
The question is how much volume of the original PCR do you need to obtain 267ngs?
Here now n = 267g and c equals your measured concentration. Let's assume your measured c = 56 ng/ul for an assumed sample. Than we can resolve the equation as follows.
n = c*V -> V = n/c -> 267ng/56ng/ul = 4.7 ul
So you need to use 4.7ul in 20ul total volume to obtain 267ng. This means you can combine 13.7ul H20 with 4.7ul of your combined PCR sample. Vortex it and spin down.
In case you concentration is < 13.33 ng/ul use 20ul of sample as stock without dilution.